tag:blogger.com,1999:blog-1020546589990477066.post8190114901827757757..comments2024-06-21T23:34:07.815-06:00Comments on Paige Taylor Evans: The One when I Reached in a Skittles BagPaige Taylor Evanshttp://www.blogger.com/profile/08460741453773142787noreply@blogger.comBlogger4125tag:blogger.com,1999:blog-1020546589990477066.post-78561152185960706602008-04-21T13:05:00.000-06:002008-04-21T13:05:00.000-06:00Who am I to dispute any of these claims because st...Who am I to dispute any of these claims because stats was my least favorite class in college. I approached the problem in a different way. The first dip into the skittles bag is free (40/40 of picking a color :-) ). The next pick, there are 39 skittles left, with 32 of them being a different color than the first one picked. There's a 32/39 chance you'll pick a different color. On the third pick, there are 24 skittles left out of the 38 that are a different color (24/38). On the forth pick, there are 16 out of 37 of a different color (16/37). On the last pick, there are 8 out of 36 of the remaining color (8/36). Multiple those together: 40/40 * 32/39 * 24/38 * 16/37 * 8/36 = .05 which means there's a 5% change of reaching into a bag of skittles and picking 5 skittles and grabbing one of each color.tomashttps://www.blogger.com/profile/14621126756934882926noreply@blogger.comtag:blogger.com,1999:blog-1020546589990477066.post-77276467227771025462008-04-20T22:09:00.000-06:002008-04-20T22:09:00.000-06:00Not to argue with Rog, but I would run a probabili...Not to argue with Rog, but I would run a probability equation meaning that you have a 1/5 chance of grabbing each one. You then take that and multiply 1/5 x 1/5 repeated 5 times which would put you at a 1/3125 probability. Or a .032% chance of that happening. Now given the amount of skittles handfuls that I have observed you taking, I would imagine that you should experience that 12 more times in your life! :)... ;)andy and camihttps://www.blogger.com/profile/08349758129552202877noreply@blogger.comtag:blogger.com,1999:blog-1020546589990477066.post-35158220518507896792008-04-17T21:39:00.000-06:002008-04-17T21:39:00.000-06:00The Chances would be the Number of Skittles in the...The Chances would be the Number of Skittles in the bag (about 40 i think) divided by 5 (equals 8). Then you take that number's Factorial (e.g. 8! = 8*7*6*5*4*3*2*1 = 40320)<BR/>So the chances are 1 in 40320 to get one of each color. if you feel this is a sufficient calculation then you can give the free scrapbook supplies to Tasha :) I could be wrong. I'm not completely sure, but Tasha Thinks I'm silly for trying to figure it out. Oh yeah I'm Tasha's Husband Roger.Roghttps://www.blogger.com/profile/05996854978539587581noreply@blogger.comtag:blogger.com,1999:blog-1020546589990477066.post-58368373265533599002008-04-17T17:46:00.000-06:002008-04-17T17:46:00.000-06:00You are so funny!You are so funny!Rappleye Familyhttps://www.blogger.com/profile/14542305922885164723noreply@blogger.com